Answer:
![a=3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7theyju5xiuykuqovlvwl2kcbogphv2y63.png)
Explanation:
So we have the equation:
![4x-2(x+a)=8](https://img.qammunity.org/2021/formulas/mathematics/high-school/slhs1ydlni381zu6mh4i9tnljiosxu8agb.png)
And we want to find a such that x = 7 is a possible solution.
To do so, substitute 7 for x. Thus:
![4(7)-2(7+a)=8](https://img.qammunity.org/2021/formulas/mathematics/high-school/mcw31baifcqdyf42myywawtyyjlobfuoqc.png)
Multiply the left and distribute the right:
![28-14-2a=8](https://img.qammunity.org/2021/formulas/mathematics/high-school/cnbio07d95bvp91tzacnymrbq8505ai9m5.png)
Subtract:
![14-2a=8](https://img.qammunity.org/2021/formulas/mathematics/high-school/jc0negj3i7zoj0umg9j4htcacfo7aj2xcy.png)
Subtract 14 from both sides:
![-2a=-6](https://img.qammunity.org/2021/formulas/mathematics/high-school/5hae5kyds95s7nr3ttmhzdny9n44xkthcc.png)
Divide by -2: "
![a=3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7theyju5xiuykuqovlvwl2kcbogphv2y63.png)
So, the value of a is 3.
And our equation would be:
![4x-2(x+3)=8](https://img.qammunity.org/2021/formulas/mathematics/high-school/uww4e3atg8aslvxivbgnfar4jyrj8ku7lg.png)
And we're done!
Edit: Incorrect Answer