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Please solve this question ​

Please solve this question ​-example-1
User Keith Vinson
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1 Answer

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Answer: x = 0.18 and x = -1.85

Work Shown:


x = (-b\pm√(b^2-4ac))/(2a)\\\\x = (-5\pm√((5)^2-4(3)(-1)))/(2(3))\\\\x = (-5\pm√(37))/(6)\\\\x \approx (-5\pm6.08276253)/(6)\\\\x \approx (-5+6.08276253)/(6) \ \text{ or } \ x \approx (-5-6.08276253)/(6)\\\\x \approx (1.08276253)/(6) \ \text{ or } \ x \approx (-11.08276253)/(6)\\\\x \approx 0.18046042 \ \text{ or } \ x \approx -1.84712707\\\\x \approx 0.18 \ \text{ or } \ x \approx -1.85\\\\

I used the quadratic formula.

Visual confirmation is shown below. The solutions are the x coordinates of the x intercepts, aka roots. GeoGebra is another tool you can use if you prefer that over Desmos. Both are free apps.

Please solve this question ​-example-1
User Regressor
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