Question

5(3x)-7y2=?,when x=3 and y =2

Answer 1

17

Step-by-step explanation:

We are given the equation:

`5(3x)- 7y^2`

and asked to solve when x=3 and y=2. Therefore, we must plug 3 in for x and 2 in for y.

`5(3(3))-7(2)^2`

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Addition and Subtraction.

Solve the exponent first.

⇒ (2)²= 2*2=4

`5(3(3))-7(4)`

Multiply 3 and 3.

⇒3*3=9

`5(9)-7(4)`

Multiply 5 and 9.

⇒5*9=45

`45-7(4)`

Multiply 7 and 4.

⇒ 7*4=28

`45-28`

Subtract 28 from 45.

`17`

5(3x)-7y² when evaluated for x=3 and y=2 is 17