Question

Given f(x) = 52x, evaluate f-1), f(o), and K2).

01/25, 1, 625

Answer 1

`f(-1) = (5)/(2)`

`f(0) = 5`

`f(2) = 20`

Explanation:

Given

`f(x) = 5(2^x)`

Required

Determine f(-1); f(0) and f(2)

Solving f(-1)

In this case, we simply take x as;

`x = -1`

Substitute -1 for x in
`f(x) = 5(2^x)`

`f(-1) = 5(2^(-1))`

Apply law of indices

`f(-1) = 5 * (1)/(2)`

`f(-1) = (5)/(2)`

Solving f(0)

In this case, we simply take x as;

`x = 0`

Substitute 0 for x in
`f(x) = 5(2^x)`

`f(0) = 5(2^0)`

`f(0) = 5(1)`

`f(0) = 5`

Solving f(2)

In this case, we simply take x as;

`x = 2`

Substitute 2 for x in
`f(x) = 5(2^x)`

`f(2) = 5(2^2)`

`f(2) = 5(4)`

`f(2) = 20`