Question

A wooden cube of side 5cm float in water 2.0cm of its depth below the water surface and its sides are vertical calculate the density of the wood in gcm^-3. ( Density of water= 1gcm^-3)​

Answer 1

The density of the wooden cube is
`\delta= 0.4 \, (g)/(cm^3)`

Step-by-step explanation:

Recall that the weight of the entire piece of wood that is floating must equal the weight of the displaced water in the case we have an object under flotation.

At the same time. we have a relationship between Volume (V), Weight (w) and density
`(\delta)` given by the formula:

`w=\delta\,*\,V`

Since both weights must be the same, we can write the following equation:

`w_(wood) = w_(water)\\\delta *\,(5\,\,cm)^3= ((1\,g)/(cm^3) )\,(2\,*5^2) cm^3\\\delta= (2)/(5) \, (g)/(cm^3) \\\delta= 0.4 \, (g)/(cm^3)`