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During a backgammon game, Jimmy rolled two dice on the board. Find the probability that the sum obtained was greater than 8 given that the number on one die was a 6

User Vinniyo
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1 Answer

4 votes

Answer:

2/3

Explanation:

This problem bothers on probability

Given that two dice are expected to give an outcome of sum greater than 8

But in the problem statement the first die is already settled since it is showing 6 already.

Now for the second die, the possible outcomes that will add up with the first die to produce a figure greater than 8 are (3,4,5,6)

The probability of obtaining either of these numbers is 4/6= 2/3

Having the first die settled, this means that the probability of obtaining a sum of 8 is 2/3

User Jazzmin
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