Question

Please help me fast:

Before a sale, an item’s price was $45.00. After the sale discount the price became $38.25. What was the percent of the sale discount?

Solve:
d
5.6−7y=−4(2y−0.9)+2.4

Answer 1

Explanation:

Before a sale 45.00$

original price p =$45.00

After the sale discount, the price became $38.25

Difference of sale = 45.00-38.00= $7.00

% of sale distance =Difference of sale/p x%100

=%15

Answer 2

45 − x % ∗ 45 = 38.25

− 45 x /100 = 38.25 − 45

− 45 x /100 = − 6.75

x = 6.75 ∗ 100 /45

= 15