Complete question :
The University but a total of 2200 computers they bought three kinds of computers HP, IBM and dell. The ratio of theNumber of HP computers to IBM to dell is 2:3:6 each HP computer cost $750 each dell computer cost 90% of the price of an HP computer if the University spent a total of $1,650,000 what is the total cost of each IBM computer
Answer:
$900
Explanation:
Given that :
Total amount of computers purchased = 2200
Number of brands purchased = 3;
HP, IBM and DELL
The ratio of theNumber of HP computers to IBM to dell is 2:3:6
Cost per HP = $750
Cost per Dell = 90% of HP = 0.9 × $750 = $675
Total amount spent = $1,650,000
2:3:6 = (2+3+6) = 11
Number of IBM computers purchased :
(3/11) * 2200 = 600 IBM
(2/11) * 2200 = 400 HP
(6/11) * 2200 = 1200 DELL
TOTAL Cost of HP = (400 × $750) = $300,000
TOTAL cost of Dell = (1200 * $675) = $810,000
TOTAL cost of IBM :
$1,650,000 - ($300,000 + $810,000)
$1,650,000 - $1,110,000 = $540,000
Cost of each IBM:
540,000 / 600 = $900