Complete question:
Two six-sided dice are rolled (one red one and one green one). Some possibilities are (Red= 1, Green=5) or (Red=2, Green=2) etc.
a)How many total possibilities are there?
For the rest of the questions, we will assume that the dice are fair and that all the possibilities in (a) are equally likely.
b)What is the probability that the sum on the two dice comes out to be 11?
c)What is the probability that the sum on the two dice comes out to be 7?
d)What is the probability that the numbers on the two dice are equal?
Answer:
Kindly check explanation
Explanation:
Total probabilities :
Total possible outcomes on each dice = 6
Total probabilities = 6² = 36
b)What is the probability that the sum on the two dice comes out to be 11?
Total required outcome = 2
Total possible outcomes = 36
Probability = required outcome / Total possible outcomes
P(sum on both dice = 11) = 2 / 36 = 1/18
c)What is the probability that the sum on the two dice comes out to be 7?
Required outcome = 6
Possible outcomes = 36
P(obtaining a sum of 7) = 6/36 = 1/6
d)What is the probability that the numbers on the two dice are equal
= required outcome / possible outcomes
Required outcome = 1,1 ; 2,2; 3,3; 4,4 ; 5,5 ; 6,6
= 6/36 = 1/6