Answer:
Step-by-step explanation:
At t = 1 velocity = 0
At t = 3 velocity = 3
slope of the line = 3-0 / 3-1 = 3/2
At t = 2
velocity = 3/2 x ( 2 - 1 )
= 1.5 m /s
velocity at t = 2 is 1.5 m /s
Position at t = 2 :
displacement at t = 2
area of graph upto t = 2
= 1 / 2 x 1 x 1.5 = .75
position at t = 2 :
= initial position + displacement
= 10 + .75 = 10.75 m
position at 6 s :
displacement at t = 6
area of curve upto t = 6
= 1 / 2 x 2 x 3 + 3 x 3 + 1/2 x 3 x ( 4.5 - 3 )
= 3 + 9 + 2.25
= 14.25 m
position at t = 6
= initial position + displacement
= 10 + 14.25 = 24.25 m
position at 9 s :
displacement at t = 9
area of curve upto t = 9
= 1 / 2 x 2 x 3 + 4 x 3 + 1/2 x 4 x ( 5 - 3 )- 1/2 x 2 x 1.5
= 3 + 12 + 4 - 1.5
= 17.5 m
position at t = 9
= initial position + displacement
= 10 + 17.5 = 27.5 m