Question

for f(x)=(x-3)/(x^(2)-4), the function is at x=2 continuous discontinuous with an infinite discontinuity discontinuous with a jump discontinuity discontinuous with a point discontinuity

Answer 1

`\Large \boxed{\mathrm{discontinuous \ with \ a \ point \ discontinuity}}`

`\rule[225]{225}{2}`

Explanation:

`\displaystyle f(x)=(x-3)/(x^2-4)`

When x = 2.

We can see that the denominator is equal to 0 when the input value is 2.

`2^2-4=4-4=0`

Obtaining a zero in the denominator indicates a point of discontinuity.

In the graph below, we can see that the function is discontinuous at x = 2.

`\rule[225]{225}{2}`

Answer 2

ITS UNDEFINED

Explanation:

2-3)/2^2 - 4

-1/(4-4)

-1/0

ITS UNDEFINED