Question

Solve the system of equations using substitution or elimination: 2x – y = 0 x + 3y = -14

show your work please

Answer 1

(-2,-4)

Explanation:

2x-y=0

-2(x+3y=-14)

-2x-6y=28

x terms cancel

-y+-12y=-13y

0+28=28

-7y=28

28/-7

y=-4

plug into the orginal equation

2x-(-4)=0

simply: 2x+4=0

elimante the 4

2x=-4

divide by 2

x=-2

Answer 2

x = -2 , y= -4

Explanation:

`\begin{bmatrix}2x-y=0\\ x+3y=-14\end{bmatrix}\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:2x-y=0:\quad x=(y)/(2)\\\\\mathrm{Subsititute\:}x=(y)/(2)\\\\\begin{bmatrix}(y)/(2)+3y=-14\end{bmatrix}\\\\\mathrm{Simplify}\\\\\begin{bmatrix}(7y)/(2)=-14\end{bmatrix}\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:(7y)/(2)=-14:\quad y=-4\\\\\mathrm{For\:}x=(y)/(2)\\\\\mathrm{Subsititute\:}y=-4\\x=(-4)/(2)\\\\(-4)/(2)=-2\\\\x=-2,\:y=-4`