Answer:
D) both groups are equatorial.
Step-by-step explanation:
To solve this question we can start by drawing the molecule in using the structure of the hexagon. In this structure, we have the methyl group on carbon 1 and the terbutyl group on carbon 3, additionally, if we have a cis structure both groups must have the same type of bond (in this case the wedge bond). (See figure 1)
When we write the chair structure, we must keep the same structure. That is, methyl must be on carbon 1 and terbutyl on carbon 3. Also, the cis configuration must be maintained. With this in mind, we can choose the equatorial configuration for methyl on carbon 1 (since the position equatorial is the one that has less steric impediment and more stability). If this is true for carbon 1, we must place the terbutyl group on carbon 3 in the same configuration (i.e. cis). Therefore, on carbon 3 we must place the tert-butyl down on carbon 3, that is, in the equatorial position. (See figure 1).
Therefore, in the chair-like structure, both groups must be in an equatorial position.
I hope it helps!