Question

20 POINTSS To whom ever can answer this

Answer 1

`-3/13`

Explanation:

So we have the expression:

`(y^3+√(x-2))/(|4x-y|)`

And we want to evaluate it for x=6 and y=-2.

Thus, substitute:

`=((-2)^3+√((6)-2))/(|4(6)-(-2)|)`

Let's do the numerator first:

`(-2)^3+√(6-2)`

Cube the first term and subtract under the radical:

`=-8+\sqrt4`

Simplify:

`=-8+2`

Add:

`=-6`

Now, do the denominator:

`|4(6)-(-2)|`

Multiply:

`=|24-(-2)|`

Simplify and add:

`=|24+2|\\=|26|`

Remove the absolute value bars:

`=26`

So, together:

`=((-2)^3+√((6)-2))/(|4(6)-(-2)|)\\=-6/26`

Reduce:

`=-3/13`

And that's our answer: :)