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Suppose A has a coordinate of 8 and AB = 3. What are the possible midpoints of AB?

User Tano
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1 Answer

2 votes

Answer:

The possible midpoints of AB are
(19)/(2) and
(13)/(2).

Explanation:

Let suppose that A and B have one-dimensional coordinates. GIven that
A = 8 and
AB = 3, there are two possible locations for B:


B_(1) = A+AB


B_(1) =8+3


B_(1) = 11


B_(2) = A-AB


B_(2) = 8-3


B_(2) = 5

The midpoint equations for each case are, respectively:


m_(1) = (A+B_(1))/(2)


m_(1)=(8+11)/(2)


m_(1) = (19)/(2)


m_(2) = (A+B_(2))/(2)


m_(2) = (5+8)/(2)


m_(2) = (13)/(2)

The possible midpoints of AB are
(19)/(2) and
(13)/(2).

User Thirdender
by
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