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find the area of the triangle given a = 24, b=40, and C= 55°. Round your answer to the nearest tenth. ​

find the area of the triangle given a = 24, b=40, and C= 55°. Round your answer to-example-1
User Marlhex
by
5.1k points

2 Answers

4 votes

Answer:


\huge \boxed{\mathrm{393.2 \ units^2 }}

Explanation:

We can solve for the area of the triangle when two sides are given and the angle in between the two sides.


\displaystyle A=\mathrm{(1)/(2)ab \cdot sinC }


\displaystyle A=\mathrm{(1)/(2) \cdot 24 \cdot 40 \cdot sin55 }


\displaystyle A=\mathrm{480 \cdot sin55 }


\displaystyle A=\mathrm{393.19298125...}

The area of the triangle is 393.2 units².

User Ponds
by
4.5k points
2 votes

Answer: 393.2 units²

Explanation:

Since you know the length of two sides and the measure of the included angle, you can use the following trig formula:


A=(1)/(2)ab \sin C

Given: a = 24, b = 40, C = 55°


A=(1)/(2)(24)(40) \sin 55^o\\\\.\quad =480\sin 55^o\\\\.\quad =393.2

User Darko Miletic
by
5.3k points
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