Answer:
Explanation:
x- intercept, vertex (v) and axis of symmetry, parabola form:x²+bx+c
vertex(h,k)
1- f(x)=(x+3)(x-3) change into parabola form
f(x)=x²-9 a=1,b=0 ,c=-9
h=-b/2a=0
k=f(0)=-9
vertex(0,-9) , x intercept is when f(x)=0
(x-3)(x+3)=0 either x-3=0⇒ x=3 or x+3=0 then x=-3
x=3, x=-3 (-3,0) and (3,0)
the x of symmetry is the h of the vertex=0
2-g(x)=(x+1)(x-3)
g(x)=x²-2x-3 a=1, b=-2,c=-3
h=-b/2a⇒-(-2)/2(1)⇒h=1
k=f(1)=1²-2(1)-3⇒k=-4
v(1,-4)
x of symmetry=h=1
(x+1)(x-3)=0
x+1=0⇒x=-1 (-1,0)
x-3=0 ⇒x=3 (3,0)
x intercept :-1,3
3-y=-x(x+6) ⇒y=-x²-6x a=-1,b=-6, c=0
vertex(-3,9)
x intercept:(0,0) and (-6,0)
axis of symmetry =-3
4-g(x)=2(x-5)(x-1) ⇒ 2x²-12x+10 a=2, b=-12, c=10
vertex(3,-8)
axis of symmetry=3
x intercept : (5,0), (1,0)
5) -4x(x+1)⇒-4x²-4x a=-4,b=-4
vertex(-1/2,1)
x of symmetry=-1/2
x intercept : (0,0)(-1,0)
6- f(x)=-2(x-3)² ⇒-2x²+12x-18
vertex(3,0)
x intercept (3,0)
axis of symmetry = 3