Question

Write the quadratic equation in standard form and then choose the value of "b."

(2x - 1)(x + 5) = 0
O
10
011
pllllllls help me

Answer 1

`(2x-1)(x+5)=2x^2+9x-5=0`.

The quadratic equation has a general form of

`ax^2+bx+c=0`.

So your "b" is 9.

Hope this helps.

Answer 2

Answer: Answer is in the steps

Explanation:

(2x-1)(x+5) = 0 First expand the left side by apply the distributive property twice.

(2x -1)(x+5) =0

x(2x -1) = 2x^2 -1x

5(2x -1) = 10x -5

Now rewrite them all together

2x^2 - 1x +10x -5 = 0 combine like terms on the left side.

`2x^(2)` + 9x -5 = 0 a is the first leading coefficient,b is the second leading coefficient, and c is the constant.

So in this case, the value of b is 9.