Question

a car accelerates from 10 m/s to 30 m/s as the traffic break up on the highway. the acceleration occurs over 3.5 seconds of time. determine the acceleration of the car.

Answer 1

`\boxed{\sf Acceleration \ (a) = 5.7 \ m/s^2}`

Given:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Time taken (t) = 3.5 seconds

To Find:

Acceleration (a) of the car

Step-by-step explanation:

From equation of motion:

`\boxed{ \bold{ v = u + at}}`

Substituting value of v, u & t in the equation:

`\sf \implies 30 = 10 + a(3.5) \\ \\ \sf \implies 30 - 10 = 3.5a \\ \\ \sf \implies 20 = 3.5a \\ \\ \sf \implies 3.5a = 20 \\ \\ \sf \implies a = (20)/(3.5) \\ \\ \sf \implies a = 5.7 \: m/s^2`

`\therefore`

Acceleration (a) of the car = 5.7 m/s²