Question

What is the final temperature of a 2.50 L system when its volume is reduced to 1.75 L if the initial temperature was 298 K?

Answer 1

208.6 K

Step-by-step explanation:

V1/T1 = V2/T2

T2 = T1 V2 / V1

T must be in K units

T2 = 298 * 1.75 / 2.5 = 208.6 K