Question

In a different plan for area​ codes, the first digit could be any number from 2 through 5​, the second digit was either 2, 3, 4, or 5​, and the third digit could be any number except 4, 5, or 8. With this​ plan, how many different area codes are​ possible?

Answer 1

Explanation:

First digit 2,3,4,5 = 4 different digits.

Second digit 2,3,4,5 = 4 different digits.

Third digit = 1,2,3,6,7,9 = 6 different digits.

Total number of possibilities = 4*4*6 = 96