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Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day. If r percent of the store's revenue from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of Newspaper B. Write an expression in terms of r and p.

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Answer:


\mathbf{r = (400p )/( 500 -p)}

Explanation:

Given that:

Last Sunday a certain store sold copies of Newspaper A for $1.00 each

A = 1

and copies of Newspaper B for $1.25 each,

B = 1.25

and the store sold no other newspapers that day. If r percent of the store's revenue from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of Newspaper B.

Then ;


r = (A)/(A+1.25B) * 100 --- (1)


p = (A)/(A+B) * 100 --- (2)

From (2)


A+B = (A)/(p) * 100


B = (A)/(p) * 100-A


B = (A( 100-p))/(p)

Substituting the value of B into equation (1), we have:


r = \frac{A}{A+1.25 * { (A( 100-p))/(p)}} * 100


r = \frac{A}{A+1.25 * { A( 100-p)}} * 100p


r = (100p)/(p+125 -1.25 p)


r = (100p)/(125 -0.25 p)

multiplying both numerator and denominator by 4; we have


r = (4(100p) )/( 4(125 -0.25) p)


\mathbf{r = (400p )/( 500 -p)}

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