Answer:
9 times
Explanation:
Given
![Number = 3355](https://img.qammunity.org/2021/formulas/mathematics/college/mlcty6vp8ji97iz340ylmc0ptq29orgb3y.png)
Required
Determine how many times, the 3 on the left is greater than that on the right
![Number = 3355](https://img.qammunity.org/2021/formulas/mathematics/college/mlcty6vp8ji97iz340ylmc0ptq29orgb3y.png)
First, we need to determine the value of the three on the left
To get its value, we have to change all other digits to 0. This gives
![Left\ 3 = 3000](https://img.qammunity.org/2021/formulas/mathematics/college/s9jj32scoqrxwd0o52vovqz9zt1526zvv5.png)
Next, we need to determine the value of the three on the righy
Similarly, we have to change all other digits to 0. This gives
![Right\ 3 = 0300](https://img.qammunity.org/2021/formulas/mathematics/college/ijpwl655y8z9r27jybfrsn1eqtweay9pho.png)
![Right\ 3 = 300](https://img.qammunity.org/2021/formulas/mathematics/college/1zkm2dows872zu5odc17nboqff0kud3lp1.png)
Next, we calculate the positive difference between these two values and divide by the value of the Right 3
![Result = (Left\ 3 - Right\ 3)/(Right\ 3)](https://img.qammunity.org/2021/formulas/mathematics/college/dj4e9wuil0cbqzj4f356p752ukuuwk9xf6.png)
![Result= (3000 - 300)/(300)](https://img.qammunity.org/2021/formulas/mathematics/college/lyfg330b6m47noi50dzqtn3tcajpyqs0dq.png)
![Result= (2700)/(300)](https://img.qammunity.org/2021/formulas/mathematics/college/e1nbkrbuhz71hogd00mea7k7fu2m98w0xb.png)
![Result = 9](https://img.qammunity.org/2021/formulas/mathematics/college/7h9auf5wg38ipcou1y1jug1mgxat612ckb.png)
Hence, the left 3 is 9 times greater than the right 3