Question

Please answer this question​

Answer 1

(a+2)/(a-1)

Explanation:

[(a^2+5a+6)/(a^2-1)]/[(a^2-9)(a^2-2a-3)]

[(a^2+5a+6)/(a^2-1)]*[(a^2-2a-3)(a^2-9)]

[(a^2+3a+2a+6)/(a-1)(a+1)]*[(a^2-3a+a-3)/(a-3)(a+3)]

[a(a+3)+2(a+3)/(a-1)(a+1)]*[(a(a-3)+1(a-3)/(a-3)(a+3)]

[(a+2)(a+3)/(a-1)(a+1)]*[(a+1)(a-3)/(a-3)(a+3)]

=(a+2)/(a-1)