Question

a right triangle has side lengths 8 15 and 17 as shown below use these lengths to find tan B sin B and cosine B​

Answer 1

sin(B) =
`(15)/(17)`

cos(B) =
`(8)/(17)`

tan(B) =
`(15)/(8)`

Explanation:

I always find it easiest to model out the triangle: Angle B will be at the converging point of a and c.

Using SOH CAH TOA, we know that the Sin of an angle will be its opposite over hypotenuse. The opposite is 15, and the hypotenuse is 17.

So
`(15)/(17)` is the sin of B.

We also know that the cosine of B will be it's adjacent over hypotenuse. The adjacent is 8 and the hypotenuse is 17, so

`(8)/(17)`

Lastly, we know the tangent of B will be it's opposite over adjacent. The opposite of B is 15, and it's adjacent is 8, so

`(15)/(8)` is the tangent of B.

Hope this helped!