Answer:
Option C : P = $1040
Explanation:
Using formula for continuous compounding, we have;
FV = Pe^(rt)
Where;
FV is the future value
P is the starting principal
r is the interest rate
t is time period
Now, from the question;
After 9 years, value is 1,866.79
Hence;
Pe^(9r) = 1,866.79 - - - eq1
Also, after 18 years;
Pe^(18r) = $3,350.87
Now, from exponential functions,
e^(4) can be written as (e^(2))²
Thus,in our case, e^(18r) can simply be written as (e^(9r))²
Thus, we can write Pe^(18r) = $3,350.87 as;
P(e^(9r))² = 3,350.87 - - - eq3
Thus, dividing eq 1 by eq 3 gives;
P(e^(9r))²/Pe^(9r) = 3350.87/1866.79
e^(9r) = 1.794990331
So;
In 1.794990331 = 9r
r = 0.585/9
r = 0.065
Putting this for r in equation 1 gives;
Pe^(9 × 0.065) = 1,866.79
1.795P = 1,866.79
P = 1866.79/1.795
P = $1040