Answer:
Yes
Explanation:
Let the numbers be p q r such that p>q>r
So p + q + r = 3q
2q = p+ r
And q< p but q> c,
So by Solving this would give
q= (p+ r)/2
so q is the mean of p & r.
Since the only other number that fits is q,
Then q is the mean of the numbers p,q,r
As so q is also the median of this set
Thus proving that the mean is the same as the median.