Question

A cheetah can accelerate from rest to 25.0 m/s in 6.22 s. Assuming constant acceleration, how far has the cheetah run in this time

Answer 1

The distance covered by the cheetah during the motion is 77.75 m

Step-by-step explanation:

Given;

initial velocity of cheetah, u = 0

final velocity of cheetah, v = 25 m/s

time of acceleration, t = 6.22 s

Apply kinematic equation;

`s = ((v+u)/(2) )t`

where;

s is the distance covered by the cheetah during the motion

`s = ((v+u)/(2) )t\\\\s = ((25+0)/(2) )6.22\\\\s = 77.75 \ m`

Therefore, the distance covered by the cheetah during the motion is 77.75 m