Question

what is 31/50000 If the toxic quantity is 1.5 g of ethylene glycol per 1000 g of body mass, what percentage of ethylene glycol is fatal

Answer 1

`\%m=0.15\%`

Explanation:

Hello,

In this case, we are asked to compute the by mass percent representing the toxicity of ethylene glycol in the body mass. In such a way, since the by mass percent is computed with the shown below formula:

`\%m=(m_(ethylene \ glycol))/(m_(ethylene \ glycol)+m_(body\ mass))*100\%`

We can use the given masses to obtain:

`\%m=(1.5g)/(1.5g+1000g)*100\%\\ \\\%m=0.15\%`

Best regards.