Question

3. A ship sails 35 km on a bearing of 042º.

a) How far north has it travelled?
b) How far east has it travelled?
4 A ship sails 200 km on a bearing of 243.7°
a) How far south has it travelled?
b) How far west has it travelled?




3 and 4 please

Answer 1

3(a). The ship travelled in north is 26.0 km.

(b). The ship travelled in east is 23.4 km.

4(a). The ship travelled in south is -88.61 km.

(b). The ship travelled in west is -179.29 km.

Explanation:

Given that,

(3). Distance = 35 km

Angle = 42°

Let distance in north is y km.

We need to calculate the distance

Using vertical component

`y = d\cos\theta`

Put the value into the formula

`y = 35\cos42`

`y=26.0\ km`

Let distance in east is x km

We need to calculate the distance

Using horizontal component

`x =d\sin\theta`

Put the value into the formula

`x = 35\sin42`

`x=23.4\ km`

(4). A ship sails 200 km on a bearing of 243.7°

Let distance in south is y km.

We need to calculate the distance

Using vertical component

`y = d\cos\theta`

Put the value into the formula

`y = 200\cos243.7`

`y=-88.61\ km`

Let distance in west is x km

We need to calculate the distance

Using horizontal component

`x =d\sin\theta`

Put the value into the formula

`x = 200\sin243.7`

`x=-179.29\ km`

Hence, 3(a). The ship travelled in north is 26.0 km.

(b). The ship travelled in east is 23.4 km.

4(a). The ship travelled in south is -88.61 km.

(b). The ship travelled in west is -179.29 km.