Complete Question
A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?
State the null and alternative hypotheses for the above scenario.
Answer:
The null hypothesis is
The alternative hypothesis is
![H_a : \mu > 0.41](https://img.qammunity.org/2021/formulas/mathematics/college/o5a32r8jcvcjucizy41go07ovf3p90s91a.png)
Explanation:
From the question we are told that
The proportion is
![p = 0.41](https://img.qammunity.org/2021/formulas/mathematics/college/ce4401np04fhk2nx9zo8y5xq3a2j4h2pwe.png)
Generally the null hypothesis is
The above condition represents the null hypothesis because it contains and equality in its condition
The alternative hypothesis is
![H_a : \mu > 0.41](https://img.qammunity.org/2021/formulas/mathematics/college/o5a32r8jcvcjucizy41go07ovf3p90s91a.png)