Answer:
4 times that of nitrogen gas, N2.
Step-by-step explanation:
Let R1 be the rate of diffusion of nitrogen gas, N2.
Let R2 be the rate of diffusion of Hydrogen gas, H2.
Let M1 be the molar mass N2
Let M2 be the molar mass of H2.
Next, we shall determine the molar mass of N2 and H2.
This is illustrated below below:
Molar mass of N2 (M1) = 2 x 14 = 28 g/mol
Molar mass of H2 (M2) = 2 x 1 = 2 g/mol
Finally, we shall determine the rate of diffusion of Hydrogen gas, H2 as follow:
R1/R2 = √(M2/M1)
M1 = 28
M2 = 2
R1/R2 = √(M2/M1)
R1/R2 = √(2/28)
R1/R2 = √(1/14)
R1/R2 = 0.27
Cross multiply
R1 = R2 × 0.27
Divide both side by 0.27
R2 = R1/0.27
R2 = R1 × 1/0.27
R2 = R1 × 4
R2 = 4R1
Therefore, the rate of diffusion of H2 (R2) is 4 times that of N2 (R1)