Question

A charged particle has mass 1.20kg and charge negative 0.002C. It is moving. There is a uniform magnetic field of strength 0.25T pointing in the positive z direction present everywhere in the room. The particle experiences a magnetic force of 0.015N in the positive x direction. What is the velocity of the particle

Answer 1

The velocity of the particle is 30 m/s.

Step-by-step explanation:

The velocity can be found using Lorentz force:

`F = q*v * B`

Where:

q: is the charge of the particle = 0.002 C

v: is the velocity of the particle

B: is the magnetic field = 0.25 T

F: is the magnetic force = 0.015 N

Since the magnetic field and the particle's velocity are orthogonal, the cross product is equal to the product of the absolutes values of v and B.

We have:

`F = q|v||B|`

`v = (F)/(qB) = (0.015 N)/(0.002 C*0.25 T) = 30 m/s`

Therefore, the velocity of the particle is 30 m/s.

I hope it helps you!