Question

In a fixed cylinder are 3moles of oxygen gas at 300Kelvin and 1.25atm. What is the volume of the container?

Answer 1

The volume of the container is 59.112 L

Step-by-step explanation:

Given that,

Number of moles of Oxygen, n = 3

Temperature of the gas, T = 300 K

Pressure of the gas, P = 1.25 atm

We need to find the volume of the container. For a gas, we know that,

PV = nRT

V is volume

R is gas constant, R = 0.0821 atm-L/mol-K

So,

`V=(nRT)/(P)\\\\V=(3\ mol* 0.0821\ L-atm/mol-K * 300\ K)/(1.25\ atm)\\\\V=59.112\ L`

So, the volume of the container is 59.112 L