Question

Suppose a 1300 kg car is traveling around a circular curve in a road at a constant

9.0 m/sec. If the curve in the road has a radius of 25 m, then what is the
magnitude of the unbalanced force that steers the car out of its natural straight-
line path?

Answer 1

F = 4212 N

Step-by-step explanation:

Given that,

Mass of a car, m = 1300 kg

Speed of car on the road is 9 m/s

Radius of curve, r = 25 m

We need to find the magnitude of the unbalanced force that steers the car out of its natural straight- line path. The force is called centripetal force. It can be given by :

`F=(mv^2)/(r)\\\\F=(1300* 9^2)/(25)\\\\F=4212\ N`

So, the force has a magnitude of 4212 N