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19 votes
19 votes
1
Work out the sizes of the unknown angles.
a
66°
63
50°
1090

1 Work out the sizes of the unknown angles. a 66° 63 50° 1090-example-1
User Calin Leafshade
by
2.5k points

2 Answers

15 votes
15 votes

Answer:

110 degrees,

Explanation:

The unmarked external angle = 180-109 = 71 degrees.

x = 360 - 63 - 66 - 50 - 71 = 110.

User Rik De Peuter
by
3.0k points
27 votes
27 votes

Answer:

x = 110°

Explanation:

the sum of the exterior angles of a polygon = 360°

the exterior angle to 109° is

180° - 109° = 71° ( adjacent angles on a straight line )

then summing the exterior angles and equating to 360°

63° + 66° + 50° + x + 71° = 360° , that is

250° + x = 360° ( subtract 250° from both sides )

x = 110°

User Trilok Nagvenkar
by
3.2k points