Question

7. 4y(5y - 11) – 2y(3y + 10)

Answer 1

`14y^(2) -64y`

Explanation:

Hello!

4y(5y - 11)

Distribute the 4y

4y * 5y = 20y^2

4y * -11 = -44y

Put it together

20y^2 - 44y

2y(3y + 10)

Distribute the -2y

-2y * 3y = -6y^2

-2y * 10 = -20y

Put it gether

-6y^2 - 20y

Put it all together

20y^2 - 44y - 6y^2 - 20y

Combine like terms

14y^2 - 64y

The answer is
`14y^(2) -64y`

Hope this helps!