Question

How to solve 1/2(x-3)=9 linear equation

Answer 1

`\boxed{ \bold{ \sf{ \boxed{x = 21}}}}`

Explanation:

`\sf{ (1)/(2) (x - 3) = 9}`

Distribute 1/2 through the parentheses

⇒
`\sf{ (1)/(2) x - (1)/(2) * 3 = 9}`

Multiply the fractions

⇒
`\sf{ (1)/(2) x - (1 * 3)/(2 * 1) = 9}`

⇒
`\sf{ (1)/(2) x - (3)/(2) = 9}`

While performing the addition or subtraction of like fractions, you just have to add or subtract the numerator respectively in which the denominator is retained same.

⇒
`\sf{ (x - 3)/(2) = 9}`

Apply cross product property

⇒
`\sf{x - 3 = 9 * 2}`

Multiply the numbers

⇒
`\sf{x - 3 = 18}`

Move 3 to right hand side and change it's sign

⇒
`\sf{x = 18 + 3}`

Add the numbers

⇒
`\sf{x = 21}`

Hope I helped!

Best regards!!