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Which of the following values of x satisfy the equationbegin equation . . . 2 times x raised to the second power, plus 7 times x, plus 3 . . . equals 0 . . . end equation?

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So the equation is 2x^2 + 7x + 3 = 0, let’s factor this out: 2x^2 + 6x + x + 3 = 0, so 2x(x+3) + 1(x+3) = 0, so (2x+1)(x+3)=0, so x = -1/2 or -3
User RChugunov
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