Question

Find the distance between A(5,-8) and B(2,9) to the nearest hundredth.

Answer 1

The answer is 17.26 units

Explanation:

The distance between two points can be found using the formula

`d = \sqrt{ ({x1 - x2})^(2) + ({y1 - y2})^(2) } \\`

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

A(5,-8) and B(2,9)

The distance between them is

`|AB| = \sqrt{ ({5 - 2})^(2) + ({ - 8 - 9})^(2) } \\ = \sqrt{ {3}^(2) + ({ - 17})^(2) } \\ = √(9 + 289) \\ = √(298)`

| AB | = 17.26267

We have the final answer as

17. 26 units to the nearest hundredth

Hope this helps you