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The vector parametric equation for the line through the points (−1,−4,2) and (−1,0,−3) is:_______

User Pengibot
by
5.3k points

1 Answer

2 votes

Answer:
x(t)=-1


y(t)=-4+4(t)


z(t)=2-5(t)

Explanation:

To find: The vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3).

Let A (−1,−4,2) and B(−1,0,−3)

First we find direction vectors :
\overrightarrow{AB}=<-1-(-1),0-(-4),-3-2>


<0,4,-5>

Now, the parametric equations of the line:


x(t)=-1+0(t)


y(t)=-4+4(t)


z(t)=2-5(t)

Hence, the vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3):


x(t)=-1


y(t)=-4+4(t)


z(t)=2-5(t)

User Mahesh Giri
by
5.3k points
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