Answer:
Two solutions.
![x = 8, -6](https://img.qammunity.org/2021/formulas/mathematics/high-school/y84rkfy25a9hi2qnncm34h4lpjy8e62eem.png)
Explanation:
Given the equation:
![\left|x-1\right|=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/cegd97a6ywmfd68u4b7snvzaz8ov4l64wc.png)
To find:
Number of solutions to the equation.
Solution:
First of all, let us learn about modulus function.
![|x|=\left \{ {{x\ if\ x>0} \atop {-x\ if\ x<0}} \right.](https://img.qammunity.org/2021/formulas/mathematics/high-school/pxb3z67ufcwgadf7c9athpls30clmbfu61.png)
i.e. Modulus function changes to positive by adding a negative sign to the negative values.
It has a value equal to
when
is positive.
It has a value equal to -
when
is negative.
Here, the function is:
![|x-1|=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/3wdmqhr9en1ihimhecdej0ny49r7m9j2tm.png)
So, two values are possible for the modulus function:
![\pm(x-1)=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/bqsn9olxfi1pao4hd07l5d0hv4lfhqf0t4.png)
Solving one by one:
![x-1 = 7\\\Rightarrow x =8](https://img.qammunity.org/2021/formulas/mathematics/high-school/7wvquv1u9r4t25zni9w3nius93kck780fi.png)
![-(x-1) = 7\\\Rightarrow -x+1=7\\\Rightarrow x = -6](https://img.qammunity.org/2021/formulas/mathematics/high-school/kw6d0qs3jaguqvc2yme63ycw2ydrmq5kta.png)
So, there are two solutions,
![x = 8, -6](https://img.qammunity.org/2021/formulas/mathematics/high-school/y84rkfy25a9hi2qnncm34h4lpjy8e62eem.png)