Question

A particle with charge -5 C initially moves at v = (1.00 i^ + 7.00 j^ ) m/s. If it encounters a magnetic field B =80 Tkˆ, find the magnetic force vector on the particle.

Answer 1

The magnetic force vector on the charged particle with a velocity of (1.00i^ + 7.00j^) m/s in a magnetic field of B = 80 Tk^ is (-560i^ + 400j^) T C m/s.

Step-by-step explanation:

To find the magnetic force vector on a particle, we can use the formula F = qv x B, where F is the force, q is the charge, v is the velocity, and B is the magnetic field. In this case, the charge of the particle is -5 C and the velocity is (1.00i^ + 7.00j^) m/s. The magnetic field is given as B = 80 Tk^.

Substituting the values into the formula, we get F = (-5 C)(1.00i^ + 7.00j^) m/s x (80 Tk^).

Calculating the cross product, we find that the magnetic force vector on the particle is (-560i^ + 400j^) T C m/s.