Question

How do you solve this systems of equations problem

2r +3s=-5
6s=2r

Answer 1

see explanation

Explanation:

Given the 2 equations

2r + 3s = - 5 → (1)

6s = 2r → (2) ( divide both sides by 2 ), then

r = 3s

Substitute r = 3s into (1)

2(3s) + 3s = - 5

6s + 3s = - 5

9s = - 5 ( divide both sides by 9 )

s = -
`(5)/(9)`

Substitute this value into either of the 2 equations and evaluate for r

Substituting into r = 3s, then

r = 3 × -
`(5)/(9)` = -
`(5)/(3)`

Solution is r = -
`(5)/(3)` and s = -
`(5)/(9)`