Question

A box at rest on a ramp at an incline of 22°. The normal force on the box is 538 N

Answer 1

F = 580.25 N

Step-by-step explanation:

It is given that,

A box at rest on a ramp at an incline of 22°

The normal force on the box is 538 N

We need to find the gravitational force on the box.

The force of gravity acting on an object is equal to its weight. So,

F = mg

But here the box is incline at an angle of 22 degrees

It means that mg will resolve in rectangular components such that, normal force is :

`N=mg\cos\theta\\\\mg=F=(N)/(\cos\theta)\\\\F=(538)/(\cos22)\\\\F=580.25\ N`

So, the gravitational force on the box is 580.25 N.