65.9k views
18 votes
One envelope contains only $5 bills, another envelope contains only $10 bills, another envelope contains only $20 bills, and the last envelope contains only $50 bills. No envelopes are empty and each of the four contains the same number of bills. All of the bills are exchanged for $100 bills (the total dollar amount remains same). Find the least possible total number of bills in all four envelopes.

User Mokshino
by
3.7k points

1 Answer

7 votes

Answer:

The least possible number is 20 bills in each envelope, which means 80 total bills. With a total of $1700

Explanation:

-Okay so what they are asking is the least number of bills in each of the envelopes, WHILE the total can be exchanged for $100 only and all the envelopes have the exact same amount of bills.

5 + 10 + 20 + 50 = $85

(adding these totals because they told us to have equal amounts of bills in each envelope)

85 x n = (number divisible by 100)

n = number of bills

first least number possible was 20

85 x 20 = 1700

User Maxem
by
3.8k points