Answer:
The student must score at least 76 in the third subject
Explanation:
Given
Scores in 2 subjects = 77 and 72
Number of subjects = 3
Required
Determine the scores in the third subject to get an average of 75
Represent the score in the third subject with y
Average in 3 scores is calculated as thus;
![Average = (Sum\ of\ 3\ scores)/(3)](https://img.qammunity.org/2021/formulas/mathematics/college/zz9ow65qu56pvm22ea92gog7usdbkhk8ak.png)
Substitute 75 for Average
![75 = (Sum\ of\ 3\ scores)/(3)](https://img.qammunity.org/2021/formulas/mathematics/college/jzn7yrcd42qn1yzdnjdfu65yp8o4skl3kg.png)
Multiply both sides by 3
![3 * 75 = (Sum\ of\ 3\ scores)/(3) * 3](https://img.qammunity.org/2021/formulas/mathematics/college/gqkj3qzjf2stxqceifamdxcbypsafndbxt.png)
![3 * 75 = Sum\ of\ 3\ scores](https://img.qammunity.org/2021/formulas/mathematics/college/c20ecku24e732dulqd4078fanpqzxbzreg.png)
![225 = Sum\ of\ 3\ scores](https://img.qammunity.org/2021/formulas/mathematics/college/7o1bmsu38nflp6uhuijbvllt1e3ks9f87z.png)
Substitute (77 + 72 + y) for Sum of 3 scores
![225 = 77 + 72 + y](https://img.qammunity.org/2021/formulas/mathematics/college/a2684y102pkpv67d64t9zc0qkpq9qtjqtw.png)
![225 = 149 + y](https://img.qammunity.org/2021/formulas/mathematics/college/m32w4dcsb6quoj5xlmcqzh2sj4b5mgmzzx.png)
Subtract 149 from both sides
![225 - 149 = 149 - 149 + y](https://img.qammunity.org/2021/formulas/mathematics/college/zfhxneyq17ywy70zb58n1c6ft5qs7dy0gr.png)
![225 - 149 = y](https://img.qammunity.org/2021/formulas/mathematics/college/pi8juzu1kah5ohpbhvxbr0iyafb3za1vua.png)
![76= y](https://img.qammunity.org/2021/formulas/mathematics/college/3mlu5d6q1zfyevwa46wu04m593c3fcgyck.png)
![y = 76](https://img.qammunity.org/2021/formulas/mathematics/college/3iakca91w7j21pppbvn45pja1ilkmvuqfi.png)
Hence, the student must score at least 76 in the third subject