Question

Calculate the percentage loss of mass between the sucrose solutions 0.1 mol/dm3and 0.5 mol/dm3. Give your answer to three significant figures

Answer 1

The percentage loss in mass between sucrose solutions 0.5 mol/dm³ and 0.1 mol/dm³ is 80.0% loss in mass

Step-by-step explanation:

The molecular formula of sucrose is C₁₂H₂₂O₁₁

The molecular mass of sucrose is 342.3 g/mol

Therefore;

The mass of sucrose in 0.1 mol/dm³ solution = 0.1 × 342.3 = 34.23 g

The mass of sucrose in 0.5 mol/dm³ solution = 0.5 × 342.3 = 171.5 g

The percentage loss in mass of the sucrose is given as follows;

`Percentage \ loss \ in \ mass = (Original \ mass - New \ mass)/(Original \ mass ) * 100`

Therefore;

`Percentage \ loss \ in \ mass = (171.5 - 34.23)/(171.5) * 100 = 80.04 \%`

Which gives, the percentage loss in mass between sucrose solutions 0.1 mol/dm³ and 0.5 mol/dm³ is 80.0% to three significant figures.