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Two narrow slits spaced 100 microns apart are exposed to light of 600 nm. At what angle does the first minimum (dark space) occur in the interference pattern

1 Answer

4 votes

Answer:

The angle is
\theta = 0.1719^o

Step-by-step explanation:

From the question we are told that

The distance of separation is
d = 100 * 10^(-6) \ m

The wavelength of light is
\lambda = 600 nm = 600 *10^(-9) \ m

Generally the condition for destructive interference is mathematically represented as


dsin(\theta ) =[m + (1)/(2) ]\lambda

Here m is the order of maxima, first minimum (dark space) m = 0

So


100 *10^(-6 ) * sin(\theta ) =[0 + (1)/(2) ]600 *10^(-9)

=>
\theta = sin^(-1) [0.003]

=>
\theta = 0.1719^o

User Krash
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