Question

Two narrow slits spaced 100 microns apart are exposed to light of 600 nm. At what angle does the first minimum (dark space) occur in the interference pattern

Answer 1

The angle is
`\theta = 0.1719^o`

Step-by-step explanation:

From the question we are told that

The distance of separation is
`d = 100 * 10^(-6) \ m`

The wavelength of light is
`\lambda = 600 nm = 600 *10^(-9) \ m`

Generally the condition for destructive interference is mathematically represented as

`dsin(\theta ) =[m + (1)/(2) ]\lambda`

Here m is the order of maxima, first minimum (dark space) m = 0

So

`100 *10^(-6 ) * sin(\theta ) =[0 + (1)/(2) ]600 *10^(-9)`

=>
`\theta = sin^(-1) [0.003]`

=>
`\theta = 0.1719^o`