Question 1

G. Write the equation of the line in slope-intercept form.

1. The line containing (3,1) and is perpendicular to the y=-x+1.
2. The line passes through (-1,7) and is parallel to the 5y = 4x + 5.

Question 2

Answer:

y= x-2
y = 4/5 x+39/5

Explanation:

1.

$(3,1) and\:perpendicular \:to \: y = -x+1\\(3,1) = (x,y)\\m = -1\\In\: perpendicularism ; m_2 = (-1)/(m_1) \\m_2 = (-1)/(-1) \\m_2 =1\\y = mx+c\\1 = 1(3) +c\\1=3+c\\1-3=c\\-2 =c\\Substitute \:new \:values\:into\\y =mx+c\\y = 1x -2\\y = x-2$

2.

$(-1,7) =(x_1,y_1)\\\\5y = 4x+5\\\\Write\:in\:y=mx+c\:form\\(5y)/(5) = (4)/(5) x + (5)/(5) \\y = (4)/(5) x +1\\m = (4)/(5) \\\\y -y_1=m(x-x_1)\\y-7=(4)/(5) (x -(-1)\\y -7 = 4/5(x+1)\\y -7 = 4/5x +4/5\\\\y = (4)/(5) x+(4)/(5) +7\\\\y = (4)/(5) x +39/5$

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